Calculate the wavelength of an electron moving with a velocity of displaystyle 2-05times - 10 - 7 -m- s - -1 -

Question

Toppr Admin · Accepted Answer

The wavelength of an electron is obtained from de-Broglie equation-x3BB-hmv-xA0- -xA0- -6-626-xD7-10-x2212-34Js9-11-xD7-10-x2212-31kg-xD7-2-05-xD7-107m-s-xA0- -xA0- -3-55-xD7-10-x2212-11m

Calculate the wavelength of an electron moving with a velocity of $2.05 \times 10^{7} m s^{- 1}$ .

The wavelength of an electron is obtained from de-Broglie equation.
$λ = \frac{h}{m v}$
$= \frac{6.626 \times 10^{- 34} J s}{9.11 \times 10^{- 31} k g \times 2.05 \times 10^{7} m / s}$
$= 3.55 \times 10^{- 11} m$

Calculate the wavelength of an electron moving with a velocity of 2.05×107ms−1.

The wavelength of an electron is obtained from de-Broglie equation.λ=hmv =6.626×10−34Js9.11×10−31kg×2.05×107m/s =3.55×10−11m

Calculate the wavelength of an electron moving with a velocity of $2.05 \times 10^{7} m s^{- 1}$ .

The wavelength of an electron is obtained from de-Broglie equation.
$λ = \frac{h}{m v}$
$= \frac{6.626 \times 10^{- 34} J s}{9.11 \times 10^{- 31} k g \times 2.05 \times 10^{7} m / s}$
$= 3.55 \times 10^{- 11} m$