Question

Calculate the weight of ${CH}_4$ in $9Lt$ cylinder at $16$ atm and ${27}^{o}C$.

• A. 106.6 g
• B. 93.6 g
• C. 25.6 g
• D. 72.4 g

Answer 1

Answer: (B)

The correct option is C 93.6 g

Let the weight of methane $\left(C{H}_4\right)$ be $Wgm$.

Molecular mass of methane $\left(C{H}_4\right)=16$

Volume, $\left(V\right)=9L$

Temperature, $\left(T\right)=27℃=(273+27)K=300K$

Pressure, $\left(P\right)=16\text{atm}$

No. of moles, $\left(n\right)=\frac{\text{wt.}}{\text{Mol. wt.}}=\frac{W}{16}$

$R=0.082Latm{mol}^{-1}{K}^{-1}$

Aplying ideal gas equation, we have

$PV=nRT$

$\Rightarrow 16\times 9=\frac{W}{16}\times 0.082\times 300$

$\Rightarrow \frac{W}{16}=\frac{144}{24.6}$

$\Rightarrow W=16\times 5.85$

$\Rightarrow W=93.6g$

Hence, the weight of methne is 93.6 g.