Calculate the work done by a coolie in carrying a load of mass 10 kg on his head when he walks uniformly a distance of 5 in the (i) horizontal direction (ii) vertical direction. ( Take g=10m/s2).
500,0
0,500
1,500
500,3
A
500,3
B
1,500
C
500,0
D
0,500
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Solution
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Consider the following,
work done is written as
W = F.s = FsCosθ
here
F is the force applied, s is the displacement caused
such that
F = mg = 10 X 10 = 100 N
s
W( horizontal direction)= FsCos(0)=500J , θ is the angle between (vectors) F and s
now,
as F and s are perpendicular for vertical direction, θ = 90
thus,
W = FsCos90 = 0
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