Capacitance C-1 - 2 C-2 - 2C-3 and potential difference across C-1- C-2 and C-3 are V-1- V-2 and V-3 respectively then-V-1 - V-2 - V-3V-1 - 2V-2 - 2V-32V-1 - V-2 - V-32V-1 - 2V-2 - V-3

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Toppr Admin · Accepted Answer

Capacitance C1=2C2=2C3 and potential difference across C1,C2 and C3 are V1,V2 and V3 respectively then:V1=V2=V3V1=2V2=2V32V1=V2=V32V1=2V2=V3

Capacitance $C_{1} = 2 C_{2} = 2 C_{3}$ and potential difference across $C_{1}, C_{2}$ and $C_{3}$ are $V_{1}, V_{2}$ and $V_{3}$ respectively then:

$V_{1} = V_{2} = V_{3}$
$V_{1} = 2 V_{2} = 2 V_{3}$
$2 V_{1} = V_{2} = V_{3}$
$2 V_{1} = 2 V_{2} = V_{3}$