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Question

Capacitance of a capacitor made by a thin metal foil is 2μF. If the foil is folded with paper of thickness 0.15 mm, dielectric constant of paper is 2.5 and width of paper is 400 mm, the length of the foil will be :
  1. 0.34 m
  2. 1.33 m
  3. 13.4 m
  4. 33.9 m

A
0.34 m
B
1.33 m
C
33.9 m
D
13.4 m
Solution
Verified by Toppr

Here, let the length be l
width is, b=400mm=0.4m
thickness, t=0.15mm=15×105m

As capacitance for parallel plate capacitor is,
C=Kϵ0A/d=Kϵ0(l×b)/t
l=Ct/Kϵ0b=2×106×15×105/(2.5×8.85×1012×0.4)=33.91m

Option D is correct.

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