Cathode- - 2H - 2 -O- 2e - - -rightarrow - H - 2 -2- OH - - -Anode- - xOH - - -rightarrow - O - 2 - 2H - 2 -O- ye - - -Overall- - 2H - 2 -Orightarrow 2H- 2 - O - 2 -Find the value of x and y- x-2 -y - 4 x-2 - y - 2 x-4 - y - 4 x-4 - y - 2

Question

Toppr Admin · Accepted Answer

Electrolysis of water is the decomposition of water into oxygen and hydrogen due to passage of electric current. In electrolysis water splits into its atomic components hydrogen and oxygen using electricity.
$C a t h o d e : {2 H}_{2} O + {2 e}^{-} \to H_{2} + 2 {O H}^{-} A n o d e : {4 O H}^{-} \to O_{2} + {2 H}_{2} O + {4 e}^{-} O v e r a l l : {2 H}_{2} O \to 2 H_{2} + O_{2}$

Cathode: 2H2O+2e−→H2+2OH−Anode: xOH−→O2+2H2O+ye−Overall: 2H2O→2H2+O2Find the value of x and y:x=2,y=4x=2,y=2x=4,y=4x=4,y=2

Electrolysis of water is the decomposition of water into oxygen and hydrogen due to passage of electric current. In electrolysis water splits into its atomic components hydrogen and oxygen using electricity.Cathode:2H2O+2e−→H2+2OH−Anode:4OH−→O2+2H2O+4e−Overall:2H2O→2H2+O2

Cathode: ${2 H}_{2} O + {2 e}^{-} \to H_{2} + 2 {O H}^{-}$
Anode: ${x O H}^{-} \to O_{2} + {2 H}_{2} O + {y e}^{-}$
Overall: ${2 H}_{2} O \to 2 H_{2} + O_{2}$
Find the value of x and y:

$x = 2, y = 4$
$x = 2, y = 2$
$x = 4, y = 4$
$x = 4, y = 2$