Certain force acting on a 20 kg mass changes its velocity from
5 m/s to 2 m/s. Calculate the work done by the force.

Question

Certain force acting on a 20 kg mass changes its velocity from 5 ms-1- to 2 ms-1- Calculate the work done by the force-

Toppr Admin · Accepted Answer

Given - -xA0- -xA0- -xA0- -xA0- -xA0-Initial velocity -xA0- -xA0- u-5 -xA0-m-s-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-xA0-Final velocity -xA0- -xA0- v-2 -xA0-m-sThe work done is equal to the-change in the kinetic energy of an object-W-12m-v2-x2212-u2-W-12-xD7-20-xD7-22-x2212-52-x27F9-W-x2212-210 J

Certain force acting on a $20 k g$ mass changes its velocity from $5 m s^{- 1}$ to $2 m s^{- 1}$ . Calculate the work done by the force.

Given : Initial velocity $u = 5$ $m / s$
Final velocity $v = 2$ $m / s$

The work done is equal to the change in the kinetic energy of an object.
$W = \frac{1}{2} m (v^{2} - u^{2})$

$W = \frac{1}{2} \times 20 \times (2^{2} - 5^{2})$

$⟹ W = - 210$ $J$

Certain force acting on a 20 kg mass changes its velocity from 5 ms−1 to 2 ms−1. Calculate the work done by the force.

Given : Initial velocity u=5 m/s Final velocity v=2 m/sThe work done is equal to the change in the kinetic energy of an object.W=12m(v2−u2)W=12×20×(22−52)⟹W=−210 J

Certain force acting on a $20 k g$ mass changes its velocity from $5 m s^{- 1}$ to $2 m s^{- 1}$ . Calculate the work done by the force.

Given : Initial velocity $u = 5$ $m / s$
Final velocity $v = 2$ $m / s$

The work done is equal to the change in the kinetic energy of an object.
$W = \frac{1}{2} m (v^{2} - u^{2})$

$W = \frac{1}{2} \times 20 \times (2^{2} - 5^{2})$

$⟹ W = - 210$ $J$