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Standard XII
Chemistry
Question
C
H
3
M
g
X
C
H
3
C
O
O
C
2
H
5
→
A
N
a
→
B
C
2
H
5
B
r
→
C
Here, C is
:
C
2
H
5
O
C
2
H
5
C
H
3
C
O
O
C
2
H
5
(
C
H
3
)
3
C
O
C
2
H
5
C
H
3
C
O
O
C
H
3
A
C
2
H
5
O
C
2
H
5
B
(
C
H
3
)
3
C
O
C
2
H
5
C
C
H
3
C
O
O
C
2
H
5
D
C
H
3
C
O
O
C
H
3
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Solution
Verified by Toppr
In first step
C
H
3
M
g
−
X
+
C
H
3
C
O
O
C
2
H
5
d
r
y
e
t
h
e
r
−
−−−−
→
(
C
H
3
)
3
C
−
O
H
+
C
2
H
5
O
M
g
X
Here the tertiary butyl alchol formed which then reacts with
N
a
to give
(
C
H
3
)
3
C
O
−
N
a
+
0.5
H
2
So when there is primary alkyl halide reacts with alkoxide then Williamson's ether synthesis takes place rather than elimination.
Williamson's ether synthesis goes through the
S
N
2
mechanism.
Option D is correct.
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