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Question

Charge of 5μC is at each of the vertices of a regular hexagon of side 10cm. Determine the electric potential at the centre of the regular hexagon.

Solution
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For Hexagonal shape
OA=OBOC=OD=OE=OF=10cm=0.1m
Potential at O
VO=VA+VB+VC+VD+VE+VF=6VA
Due to equal of charge and distance
VA=VB=VC=VD=VE=VFVO=6×14πε0qOA=6×9×109×5×1060.1=27×105 or VO=2.7×106 volt
1763126_1836208_ans_aaadf9e72f5f46e5992b23a9819420b1.png

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