Charge 5mu C-2mu C-3mu C and -9mu C are placed on a square ABCD of side 1 cm- The net electric potential the centre is-27 KV-27 sqrt-2-times 10-5V -9 KV0 V

Question

Toppr Admin · Accepted Answer

Each change along the various is separated
from the enters O by distance, $r = \frac{a}{\sqrt{2}}$
so, $r = \frac{1}{\sqrt{2}} c m = \frac{1}{\sqrt{2}} \times 10^{- 2} m$
so potential at O,
$v = \frac{k}{r} \sum q = \frac{9 \times 10^{4}}{\frac{1}{\sqrt{2}} \times 10^{- 2}} \times (5 - 2 - 9 + 3) \times 10^{- 6} = (-) 27 \sqrt{2} \times 10^{5} v$

Charge 5μC,−2μC,3μC and −9μC are placed on a square ABCD of side 1 cm. The net electric potential at the centre is:−27KV−27√2×105V −9KV0V

Each change along the various is separatedfrom the enters O by distance, r=a√2so, r=1√2cm=1√2×10−2mso potential at O,v=kr∑q=9×1041√2×10−2×(5−2−9+3)×10−6=(−)27√2×105v

Charge $5 μ C, - 2 μ C, 3 μ C$ and $- 9 μ C$ are placed on a square ABCD of side $1$ cm. The net electric potential at the centre is:
$- 27 K V$
$- 27 \sqrt{2} \times 10^{5} V$
$- 9 K V$
$0 V$