Charged particle -charge-q- mass-m- is rotating in a circle of radius R with uniform speed V- Ratio of its magnetic moment -mu- to the angular momentum -L- iscfrac - q - 2m - cfrac - q - m - cfrac - q - 4m - cfrac - 2q - m -

Question

Toppr Admin · Accepted Answer

Magnetic moment-xA0- -x3BC-IA-q-x3BD-A -x3BC-qV2-x3C0-R-xD7-x3C0-R2-qVR2Angular momentum-xA0- L-mVRRatio-xA0-xA0- -x3BC-L-qVR2mVR-q2m

Charged particle (charge $= q$ ; mass $= m$ ) is rotating in a circle of radius $R$ with uniform speed $V$ , Ratio of its magnetic moment ( $μ$ ) to the angular momentum ( $L$ ) is
$\frac{q}{2 m}$
$\frac{q}{m}$
$\frac{q}{4 m}$
$\frac{2 q}{m}$

Magnetic moment $μ = I A = (q ν) A$
$μ = \frac{q V}{2 π R} \times π R^{2} = \frac{q V R}{2}$
Angular momentum $L = m V R$
Ratio $\frac{μ}{L} = \frac{\frac{q V R}{2}}{m V R} = \frac{q}{2 m}$

Charged particle (charge=q; mass=m) is rotating in a circle of radius R with uniform speed V, Ratio of its magnetic moment (μ) to the angular momentum (L) isq2mqmq4m2qm

Magnetic moment μ=IA=(qν)A μ=qV2πR×πR2=qVR2Angular momentum L=mVRRatio μL=qVR2mVR=q2m

Charged particle (charge $= q$ ; mass $= m$ ) is rotating in a circle of radius $R$ with uniform speed $V$ , Ratio of its magnetic moment ( $μ$ ) to the angular momentum ( $L$ ) is
$\frac{q}{2 m}$
$\frac{q}{m}$
$\frac{q}{4 m}$
$\frac{2 q}{m}$

Magnetic moment $μ = I A = (q ν) A$
$μ = \frac{q V}{2 π R} \times π R^{2} = \frac{q V R}{2}$
Angular momentum $L = m V R$
Ratio $\frac{μ}{L} = \frac{\frac{q V R}{2}}{m V R} = \frac{q}{2 m}$