Charge(Q) on capacitor( of capacitance C) and potential difference(V) across it are related as :
Q=V/C
Cannot be related
Q=C×V
Q=C/V
A
Q=C/V
B
Q=C×V
C
Q=V/C
D
Cannot be related
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Solution
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If charge Q is given to a conductor and due to this its potential increases by V, then it is found that:
Q∝V
Q=CV
where constant of proportionality C is capacitance.
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