Charges of $5 \times 1 0^{- 6}$ and $- 3 \times 1 0^{- 6} C$ are kept 16 cm apart. Find the position of points on the line joining the charges where the electric potential is zero.

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Answer 1

Potential at P iss zero
$\frac{k ( 5 \times 1 0 ^{- 6} )}{x} = \frac{k ( 3 \times 1 0 ^{- 6} )}{0 . 1 6 - x}$

$5 (0.16 - x) = 3 x$
$0.8 = 8 x$
$x = 0.1 m$
$x = 10 c m$

Answer 2

Potential at P iss zero

\frac{k ( 5 \times 1 0 ^{- 6} )}{x} = \frac{k ( 3 \times 1 0 ^{- 6} )}{0 . 1 6 - x}

5 (0.16 - x) = 3 x

0.8 = 8 x

x = 0.1 m

x = 10 c m

Charges of $5 \times 1 0^{- 6}$ and $- 3 \times 1 0^{- 6} C$ are kept 16 cm apart. Find the position of points on the line joining the charges where the electric potential is zero.

Solution

Potential at P iss zero
$\frac{k ( 5 \times 1 0 ^{- 6} )}{x} = \frac{k ( 3 \times 1 0 ^{- 6} )}{0 . 1 6 - x}$

$5 (0.16 - x) = 3 x$
$0.8 = 8 x$
$x = 0.1 m$
$x = 10 c m$

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$5 (0.16 - x) = 3 x$
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