Charges of $5×10_{−6}$ and $−3×10_{−6}C$ are kept 16 cm apart. Find the position of points on the line joining the charges where the electric potential is zero.

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Solution

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Potential at P iss zero

$xk(5×10_{−6}) =0.16−xk(3×10_{−6}) $

$5(0.16−x)=3x$

$0.8=8x$

$x=0.1m$

$x=10cm$

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