Check whether 6-n can end with the digit 0 any natural number n-

Question

Toppr Admin · Accepted Answer

If any digit has the last digit 10 that means it divisible by 10-The factor of 10-2-xD7-5-xA0-So value of 6n should be divisible by 2 and 5-Both 6n is divisible by 2 but not divisible by 5-So- it can not end with 0-

Check whether $6^{n}$ can end with the digit $0$ for any natural number $n$ .

If any digit has the last digit $10$ that means it divisible by $10.$

The factor of $10 = 2 \times 5,$

So value of $6^{n}$ should be divisible by $2$ and $5.$

Both $6^{n}$ is divisible by $2$ but not divisible by $5.$

So, it can not end with $0.$

Check whether 6n can end with the digit 0 for any natural number n.

If any digit has the last digit 10 that means it divisible by 10.The factor of 10=2×5, So value of 6n should be divisible by 2 and 5.Both 6n is divisible by 2 but not divisible by 5.So, it can not end with 0.

Check whether $6^{n}$ can end with the digit $0$ for any natural number $n$ .

If any digit has the last digit $10$ that means it divisible by $10.$

The factor of $10 = 2 \times 5,$

So value of $6^{n}$ should be divisible by $2$ and $5.$

Both $6^{n}$ is divisible by $2$ but not divisible by $5.$

So, it can not end with $0.$