Question

Check whether the following numbers form Pythagorean triplet.
$6,8,10$

Answer 1

$\begin{array}{c}Let6,8,and10bethesidesoftriangle.\\ Then,weknowthat,\\ A{B}^2+B{C}^2=A{C}^2\\ \Rightarrow \sqrt{8^2+6^2}=AC\\ \Rightarrow \sqrt{64+36}=AC\\ AC=10units\\ Hence,Thegivennumbersarepythagoreantriplet.\end{array}$