Cholrine gas is produced from HCI by the addition of-K-2SO-4KClKNO-3KMnO-4

Question

Toppr Admin · Accepted Answer

The correct option is D KMnO4KMnO4 being strong oxidising agent will oxidise CI-x2212- ion present in HCl to form chlorine gas-2KMnO4-16HCl-x2192-2KCl-2MnCl2-8H2O-5Cl2

Unknown metal	Appearance	Reactions with dilute HCl	Reaction with dilute HNO $_{3}$
(1)	Dull gray solid with white oxide coating	Dissolved with bubbles of clear gas	Dissolved with bubbles of clear gas
(2)	Solid; lustrous smooth silver-gray surface	No reaction	Dissolved with bubbles of orange gas

Cholrine gas is produced from HCI by the addition of:
$K_{2} S O_{4}$
$K C l$
$K N O_{3}$
$K M n O_{4}$

The correct option is D $K M n O_{4}$
$K M n O_{4}$ being strong oxidising agent will oxidise CI $^{-}$ ion present in HCl to form chlorine gas.
$2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 8 H_{2} O + 5 C l_{2}$

Cholrine gas is produced from HCI by the addition of:K2SO4KClKNO3KMnO4

The correct option is D KMnO4KMnO4 being strong oxidising agent will oxidise CI− ion present in HCl to form chlorine gas.2KMnO4+16HCl→2KCl+2MnCl2+8H2O+5Cl2

Cholrine gas is produced from HCI by the addition of:
$K_{2} S O_{4}$
$K C l$
$K N O_{3}$
$K M n O_{4}$

The correct option is D $K M n O_{4}$
$K M n O_{4}$ being strong oxidising agent will oxidise CI $^{-}$ ion present in HCl to form chlorine gas.
$2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 8 H_{2} O + 5 C l_{2}$