0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Comment on the thermodynamic stability of NO(g) given
12N2(g)+12O2(g)NO(g);rH=90KJMol1
NO(g)+12O2(g)NO2(g):rH=74KJMol1

Solution
Verified by Toppr

The enthalpy of formation of NO has positive value. Hence, NO is unstable. During formation of NO2, energy is released. Hence, NO2 is formed.

Was this answer helpful?
34
Similar Questions
Q1
Comment on the thermodynamic stability of NO(g) given
12N2(g)+12O2(g)NO(g);rH=90KJMol1
NO(g)+12O2(g)NO2(g):rH=74KJMol1
View Solution
Q2

Comment on the thermodynamic stability of NO(g), given

N2(g) + O2(g) → NO(g) ; ΔrHθ = 90 kJ mol–1

NO(g) +O2(g) → NO2(g) : ΔrHθ= –74 kJ mol–1

View Solution
Q3
With the following informations, determine standard Gibbs free energy of formation of N2O4(g).
12N2(g)+12O2(g) NO(g) ΔG=86.6 kJ
NO(g)+12O2(g) NO2(g) ΔG=34.82 kJ
2NO2(g) N2O4(g)ΔG=5.77 kJ
View Solution
Q4
With the following information, determine standard Gibb's free energy of formation of N2O4(g).
(i) 12N2(g)+12O2(g)NO(g) ΔG0 = 86.6 kJ
(ii) NO(g)+12O2(g)12N2(g) ΔG0 = 34.82 kJ
(iii) 2NO2(g)N2O4(g) ΔG0 = 5.77 kJ
View Solution
Q5
A reversible reaction: SO2(g)+NO2(g)SO3(g)+NO(g) ..(1), takes place in two reversible steps as given below with equilibrium constant values 2.0 and 0.45 respectively.

SO2(g)+12O2(g)SO3(g),K=2.0......(2)
NO2(g)NO(g)+12O2(g),K=0.45......(3)

The equilibrium constant Kc for reaction (1) is:

View Solution