Complete and balance the following reactions (i) 92 U235+on1→…….+52 Te 137+40 Zr97
(ii) 34 Se 86→…….+2−1eo
Let Z be the atomic number and A mass number of the unknown atom X.
For (i): As atomic number and mass number is conserved in a reaction, so 92+0=Z+52+40⇒Z=0 and 235+1=A+137+97⇒A=2
Thus, balance equation will be 92U235+0n1→20n1+52Te137+40Zr97
for (ii): 34=Z+2(−1)⇒Z=36 and 86=A+0⇒A=86
The unknown atom is an isotope of Krypton (Kr) and the balanced equation will be, 34U86→36Kr86+2−1e0