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Question

Complete the above.

Solution
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$$\textbf{Step 1: Find conditions by equating opposite sides of rectangle.}$$

$$\text{According to given diagram, we have}$$
$$2x + y + 8 = 4x - y$$
$$\Rightarrow 2x = 2y + 8$$
$$\Rightarrow x = y + 4$$ $$.......(1)$$
$$\text{Also,}$$
$$2y = x + 4$$ $$......(2)$$

$$\textbf{Step 2: Solve equations (1) and (2) using substitution method. }$$

$$\text{Substitute }x=y+4\text{ in equation (2), we get}$$
$$2y=(y+4)+4$$
$$y=8$$
$$\text{Substitute }y=8\text{ in equation (1), we get}$$
$$x=8+4=12$$
$$\Rightarrow y = 8 \ \ \& \ \ x = 12$$

$$\textbf{Step 3:Find the length and breadth of rectangle and then find perimeter and area of the rectangle.}$$

$$\text{Length}=l=4x-y=4(12)-8=40$$ $$[\because\boldsymbol{ y = 8 \ \ \& \ \ x = 12}]$$
$$\text{Breadth}=b=2y=2(8)=16$$ $$[\because\boldsymbol{ y = 8 \ \ \& \ \ x = 12}]$$
$$\text{Now,}$$
$$\text{Perimeter}= 2 ( 40 + 16)=112$$ $$[\because\textbf{Perimeter}\boldsymbol{= 2 ( l + b)}]$$
$$\text{Area}= 16 \times 40 = 640$$ $$\,[\because\textbf{Area}\boldsymbol{= l b}]$$

$$\textbf{Hence, perimeter and area of given rectangle are 112 and 640 respectively. }$$

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