Question

Complete the following nuclear reaction for $$\alpha$$ and $$\beta$$ decay:
(i) $$_{92}^{238} U \longrightarrow\, ? + \, ^4_2He + Q$$
(ii) $$_{11}^{22} Na \longrightarrow\, _{10}^{22}Ne + ? + v$$

Answer 1

i) $$_{ 92 }^{ 238 }{ U }\longrightarrow ?+_{ 2 }^{ 4 }{ He }+\lambda $$

Since $$'U'$$ gines Helium $$+'Q'$$

$$\therefore $$ It gives:-

$$_{ 92 }^{ 238 }{ U }\longrightarrow _{ 90 }^{ 234 }{ Th }+_{ 2 }^{ 4 }{ He }+Q$$

ii) $$_{ 11 }^{ 22 }{ Na }\longrightarrow _{ 10 }^{ 22 }{ Ne }+?+V$$

$$\beta$$ Particle will be given.

$$_{ 11 }^{ 22 }{ Na }\longrightarrow _{ 11 }^{ 22 }{ Ne }+\beta^++V$$