0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Complete the table.
Outermost electronic configurationGroup NumberOxidation state
$$3s^{2}\ 3p^{4}$$$$16$$$$\underline { a }$$
$$3s^{1}$$$$\underline { b }$$ $$+1$$
$$2s^{2}\ 2p^{5}$$$$\underline { c } $$$$\underline { d } $$
$$3d^{10}4s^{2}$$$$\underline { e } $$$$\underline { f } $$

Solution
Verified by Toppr


  • $$\text{Group number} \Rightarrow \text{no. of valence electron}$$
  • oxidation state : refer image
a. $$-2$$
b. $$1$$
c. $$17$$
d. $$-1$$
e. $$12$$
f. $$+2$$

Was this answer helpful?
0
Similar Questions
Q1
Complete the table.
Outermost electronic configurationGroup NumberOxidation state
$$3s^{2}\ 3p^{4}$$$$16$$$$\underline { a }$$
$$3s^{1}$$$$\underline { b }$$ $$+1$$
$$2s^{2}\ 2p^{5}$$$$\underline { c } $$$$\underline { d } $$
$$3d^{10}4s^{2}$$$$\underline { e } $$$$\underline { f } $$
View Solution
Q2
Listed below are the electronic configuration of five elements. Arrange the elements in the increasing order of metallic character:

(a) [Ar]3d104s2
(b) [Ar]4s2
(c) [Ar]3d104s24p65s2
(d) [Ar]3d104s24p5
(e) [Ar]3d104s24p65s1


View Solution
Q3
An experiment resulting in sample space as S={a,b,c,d,e,f} with P(a)=116, P(b)=116, P(c)=216, P(d)=316, P(e)=416, and P(f)=516,
Let three events A,B and C are defined as A={a,c,e}, B={c,d,e,f} and C={b,c,f}.
If P(A/B)=p1, P(B/C)=p2, P(C/Ac)=p3 and P(Ac/C)=p4, then the correct order sequance is
View Solution
Q4
M3+ ion has its electronic configuration as [Ar] 3d104s2. The element lies in:
View Solution
Q5
The electronic configurations of four elements are given below. Arrange these elements in the correct order of magnitudes (without sign) of their electron affinities:
i. 2s22p5 ii. 3s23p5
iii. 2s22p4 iv. 3s23p4
Select the correct answer using the codes given below:
View Solution