Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Standard XII
Chemistry
Question

Compound A and B respectively are:
132157.png
  1. o-Bromostyrene, benzoic acid
  2. styrene dibromide, benzoic acid
  3. m-Bromostyrene, benzaldehyd
  4. p-Bromostyrene, benzaldehyde

A
p-Bromostyrene, benzaldehyde
B
styrene dibromide, benzoic acid
C
o-Bromostyrene, benzoic acid
D
m-Bromostyrene, benzaldehyd
Open in App
Solution
Verified by Toppr

When styrene is brominated, styrene dibromide is obtained.
In this reaction a molecule of bromine is added across carbon-carbon double bond.

Oxidation of styrene with potassium permanganate gives benzoic acid.
In this reaction, the side chain is oxidized to carboxylic group.

Option D is correct.

139283_132157_ans.png

Was this answer helpful?
12
Similar Questions
Q1
How to convert benzaldehyde to benzoic acid
View Solution
Q2
Can benzaldehyde be converted to benzoic acid using the tollens reagent
View Solution
Q3

Give simple chemical tests to distinguish between the following pairs of compounds.

(i) Propanal and Propanone

(ii) Acetophenone and Benzophenone

(iii) Phenol and Benzoic acid

(iv) Benzoic acid and Ethyl benzoate

(v) Pentan-2-one and Pentan-3-one

(vi) Benzaldehyde and Acetophenone

(vii) Ethanal and Propanal

View Solution
Q4
Consider the following reaction,
PhenolZn dust−−−−→XCH3Cl−−−−−−−−→Anhyd AlCl3YAlk KMnO4−−−−−−−→Z
View Solution
Q5
How will you convert the following in not more than two steps:
(i) Benzoic acid to Benzaldehyde
(ii) Acetophenone to Benzoic acid
(iii) Ethanoic acid to 2- Hydroxyethanoic acid
View Solution