Solve
Guides
0
Question
Consider a concave mirror and convex lens (refractive index = 1.5) of focal length 10 cm each. separated by a distance of 50 cm in air (refractive index = 1) as shown in the figure. An object is placed at a distance of 15 cm from the mirror.Its erect image formed by this combination has magnification $$ M_1 $$ When the set-up is kept in a medium of refractive index 7/6 the magnification becomes $$ M_2 $$, The magnitude $$\frac {M_2}{M_1} $$ is ___________
Open in App
Solution
Verified by Toppr
Correct option is C. 7
Was this answer helpful?
0
Similar Questions
Q1
Consider a concave mirror and convex lens (refractive index = 1.5) of focal length 10 cm each. separated by a distance of 50 cm in air (refractive index = 1) as shown in the figure. An object is placed at a distance of 15 cm from the mirror.Its erect image formed by this combination has magnification $$ M_1 $$ When the set-up is kept in a medium of refractive index 7/6 the magnification becomes $$ M_2 $$, The magnitude $$\frac {M_2}{M_1} $$ is ___________
View Solution
Q2
Consider a concave mirror and a convex lens (refractive index = 1.5) of focal length 10 cm each, separated by a distance of 50 cm in air as shown in the figure. An object is placed at a distance of 15 cm from the mirror. Its erect image formed by this combination has magnification M1.When the set up is kept in a medium of refractive index 76, the magnification becomes M2. The magnitude of ∣∣∣M2M1∣∣∣ is
View Solution
View Solution
View Solution