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# Consider a drop of rain water having mass 1g falling from a height of 1km. It hits the ground with a speed of 50m/s. Take 'g' constant with a value 10m/s2. The work done by the (i) gravitational force the (ii) resistive force of airs is:(i)10J(ii)−8.75J(i)10J(ii)8.75J(i)100J(ii)−8.75J(i)1.25J(ii)−8.75J

A
(i)100J(ii)8.75J
B
(i)10J(ii)8.75J
C
(i)1.25J(ii)8.75J
D
(i)10J(ii)8.75J
Solution
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#### The correct option is A(i)10J(ii)−8.75Jm=1g=11000kg h=1km=1000mwork done by gravitional force wg−mghwg=11000×10×1000Change in kinetic energy △K.E=12mv2−0=1211000×50×50−0=1.25JWork energy theorem: wg+wairresistance=△K.E10J+resistance=1.25−10where resistance=−8.75J

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