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Question

Consider a parallel plate capacitator of capacity 10 μF filled with air. When the gap between the plates is filled partly with a dielectric of dielectric constant 4, as shown in figure, the new capacity of the capacitator is (A is the area of plates):
476183.png
  1. 20μF
  2. 40μF
  3. 2.5μF
  4. 25μF

A
25μF
B
20μF
C
2.5μF
D
40μF
Solution
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Such a configuration can be thought of as a parallel combination of two capacitors- one with area A/2 and dielectric and another with same area and without dielectric.

C1=ϵ0A2d; (for air in between)

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