Question

Consider a simple harmonic oscillator of mass 0.5 kg, force constant 10 N/m and amplitude 3 cm. The maximum speed is

• A. 0.134 m/s
• B. 0.342 m/s
• C. 0.268 m/s
• D. 0.482 m/s

Answer 1

Answer: (A)

F = kx = ma

for SHM ,

$x=Asinwt$

=> $v=Awcoswt$

=> $a=-A{\omega }^{2}sinwt$

=> $a={\omega }^{2}x$

$k=m{\omega }^2$

$k=10\frac{N}{m};m=0.5kg$

${\omega }^2=20;\omega =\sqrt{20}\frac{rad}{sec}$

$v_{max}=A\omega =\sqrt{20}\times 3cm=0.134\frac{m}{s}$