Consider a small cube of volume 1-mm-2- the centre of a circular loop of radius 10cm carrying a current of 4A- Find the magnetic energy stored inside the cube-

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Toppr Admin · Accepted Answer

Energy density B22-x3BC-0total energy stored B2V2-x3BC-0-x3BC-0i-2r-22-x3BC-0V-x3BC-0i24r2-xD7-2-4-x3C0-xD7-10-x2212-7-xD7-42-xD7-1-xD7-10-x2212-94-xD7-10-x2212-1-2-xD7-2-8-x3C0-xD7-10-x2212-4J

Consider a small cube of volume $1 {m m}^{2}$ at the centre of a circular loop of radius $10 c m$ carrying a current of $4 A$ . Find the magnetic energy stored inside the cube.

Energy density $\frac{B^{2}}{2 μ_{0}}$
total energy stored $\frac{B^{2} V}{2 μ_{0}} = \frac{{(μ_{0} i / 2 r)}^{2}}{2 μ_{0}} V = \frac{μ_{0} i^{2}}{4 r^{2} \times 2} = \frac{4 π \times 10^{- 7} \times 4^{2} \times 1 \times 10^{- 9}}{4 \times {(10^{- 1})}^{2} \times 2} = 8 π \times 10^{- 4} J$

Consider a small cube of volume 1mm2 at the centre of a circular loop of radius 10cm carrying a current of 4A. Find the magnetic energy stored inside the cube.

Energy density B22μ0total energy stored B2V2μ0=(μ0i/2r)22μ0V=μ0i24r2×2=4π×10−7×42×1×10−94×(10−1)2×2=8π×10−4J

Consider a small cube of volume $1 {m m}^{2}$ at the centre of a circular loop of radius $10 c m$ carrying a current of $4 A$ . Find the magnetic energy stored inside the cube.

Energy density $\frac{B^{2}}{2 μ_{0}}$
total energy stored $\frac{B^{2} V}{2 μ_{0}} = \frac{{(μ_{0} i / 2 r)}^{2}}{2 μ_{0}} V = \frac{μ_{0} i^{2}}{4 r^{2} \times 2} = \frac{4 π \times 10^{- 7} \times 4^{2} \times 1 \times 10^{- 9}}{4 \times {(10^{- 1})}^{2} \times 2} = 8 π \times 10^{- 4} J$