As we know that equipotential surfaces are perpendicular to the direction electric field
lines. Here electric field is in $$+\hat{z}$$ direction.
So, equipotential surfaces will be the plane perpendicular to $$z$$ axis, i.e.,
along $$x$$ -y, plane, which includes any $$x$$ or $$y$$ axes. So answers $$(b),(c)$$ and $$(d)$$ are verified respectively.