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Question

Consider a uniform electric field in the $$\hat{z}$$ direction. The potential is a constant

A
in all space.
B
on the $$x$$ -y plane for a given z.
C
for any $$x$$ for a given z.
D
for any y for a given z.
Solution
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Correct option is D. on the $$x$$ -y plane for a given z.

As we know that equipotential surfaces are perpendicular to the direction electric field
lines. Here electric field is in $$+\hat{z}$$ direction.

So, equipotential surfaces will be the plane perpendicular to $$z$$ axis, i.e.,
along $$x$$ -y, plane, which includes any $$x$$ or $$y$$ axes. So answers $$(b),(c)$$ and $$(d)$$ are verified respectively.

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