Consider the following molecules -I- H-2-O-II- H-2-S-III- H-2-Se-IV- H-2-TeArrange these molecules in increasing order of bond angle-I - II - III - IVIV - III - II - II - II - IV - IIIII - IV - III - I

Question

Toppr Admin · Accepted Answer

The increasing order of bond angle is IV-lt-III-lt-II-lt-I or H2Te-lt-H2Se-lt-H2S-lt-H2O- This is the same order in which- the electronegativity and the size of the central metal atom increases-

Consider the following molecules :
(I) $H_{2} O$
(II) $H_{2} S$
(III) $H_{2} S e$
(IV) $H_{2} T e$
Arrange these molecules in increasing order of bond angle.
$I < I I < I I I < I V$
$I V < I I I < I I < I$
$I < I I < I V < I I I$
$I I < I V < I I I < I$

The increasing order of bond angle is $I V < I I I < I I < I$ or $H_{2} T e < H_{2} S e < H_{2} S < H_{2} O$ . This is the same order in which, the electronegativity and the size of the central metal atom increases.

Consider the following molecules :(I) H2O(II) H2S(III) H2Se(IV) H2TeArrange these molecules in increasing order of bond angle.I<II<III<IVIV<III<II<II<II<IV<IIIII<IV<III<I

The increasing order of bond angle is IV<III<II<I or H2Te<H2Se<H2S<H2O. This is the same order in which, the electronegativity and the size of the central metal atom increases.

Consider the following molecules :
(I) $H_{2} O$
(II) $H_{2} S$
(III) $H_{2} S e$
(IV) $H_{2} T e$
Arrange these molecules in increasing order of bond angle.
$I < I I < I I I < I V$
$I V < I I I < I I < I$
$I < I I < I V < I I I$
$I I < I V < I I I < I$

The increasing order of bond angle is $I V < I I I < I I < I$ or $H_{2} T e < H_{2} S e < H_{2} S < H_{2} O$ . This is the same order in which, the electronegativity and the size of the central metal atom increases.