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Question

Consider the following reaction ,
CCl3CH=CH2NaBO4−−−−−−−H2O2/HOCl Product(P)
P is:
  1. CCl3CH|OHCH2Cl
  2. CCl3CH|OHCH2|OH
  3. CCl3CH|ClCH2OH
  4. CCl3CH|ClCH2|Cl

A
CCl3CH|OHCH2|OH
B
CCl3CH|ClCH2OH
C
CCl3CH|OHCH2Cl
D
CCl3CH|ClCH2|Cl
Solution
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Since, CCl3 is an electron withdrawing group product P is CCl3CH|ClCH2OH
733545_639894_ans_0e8c619e22f24f80a40196c95196fa37.png

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