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Question

Consider the following reactions. In which case the formation of product is favoured by decrease in pressure?
(1) CO2(g)+C(s)2CO(g); ΔH=+172.5 kJ
(2) N2(g)+3H2(g)2NH3(g); ΔH=91.8 kJ
(3) N2(g)+O2(g)2NO(g); ΔH=+181 kJ
(4) 2H2O(g)2H2(g)+O2(g);ΔH=484.6 kJ
  1. 2,3
  2. 3,4
  3. 2,4
  4. 1,4

A
1,4
B
2,4
C
3,4
D
2,3
Solution
Verified by Toppr

If pressure is decreased, then equilibrium shift to more gas molecules side.
Here product is favoured if product gas mole are more than reactant gas mole.
(1) CO2(g)+C(s)2CO
Here reactant gas mole= 1
Product gas moles= 2
If we reduce pressure, equilibrium shift to product side.
(4) 2H2O(g)2H2(g)+O2(g)
Reactant gas moles= 2
Product gas moles= 3
If we reduce pressure, equilibrium shift to product side

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Similar Questions
Q1
Consider the following reactions. In which case the formation of product is favoured by decrease in pressure?
(1) CO2(g)+C(s)2CO(g); ΔH=+172.5 kJ
(2) N2(g)+3H2(g)2NH3(g); ΔH=91.8 kJ
(3) N2(g)+O2(g)2NO(g); ΔH=+181 kJ
(4) 2H2O(g)2H2(g)+O2(g);ΔH=484.6 kJ
View Solution
Q2
In which of the following reactions, the formation of product is favoured by decrease in temperature?
(1) N2(g)+O2(g)2NO(g) ΔH=181
(2) 2CO2(g)2CO(g)+O2(g);ΔH=566
(3) H2(g)+I2(g)2HI(g);ΔH=94
(4) H2(g)+F2(g)2HF(g);ΔH=541
View Solution
Q3
Consider the following reactions,

C(s)+O2(g)CO2(g),ΔH=94 kcal
2CO(g)+O22CO2(g),ΔH=135.2 kcal

Then, the heat of formation of CO(g) is:

View Solution
Q4
C(s)+O2(g)CO2(g);ΔH=94kcal

2CO(g)+O2(g)2CO2(g);ΔH=135.2kcal

The heat of formation of CO(g) is :

View Solution
Q5
Given that,
C(s)+O2(g)CO2(g); ΔH=394kJ
2H2(g)+O2(g)2H2O(l); ΔH=568kJ
CH4(g)+2O2(g)CO2(g)+2H2O(l); ΔH=394kJ
Heat of formation of CH4 is :
View Solution