Consider the following representation of oxy-acid, Hn1S2On2, (where S is central sulphur atom and n1 and n2 are natural numbers). If there are two possible oxy-acid of sulphur A and B contains ratio of n2:n1 are 2 and 4 respectively, then sum of oxidation state of 'S' atom in both oxy-acid will be :
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For any oxyacid of sulphur number of H-atom =2;Hn1S2On2H2S2O3,H2S2O4,H2S2O5,H2S2O6,H2S2O7,H2S2O8.
For H2S2O4;n1n2=2;⇒ Oxidation state of sulphur atom =+3
For H2S2O6;n1n2=4;⇒ Oxidation state of sulphur atom =+6