Consider the ground state of Cr atom -Z - 24- The numbers of electrons with the azimuthal quantum numbers- l - 1 and 2 are- respectively- 16 and 412 and 412 and 516 and 5

Question

Toppr Admin · Accepted Answer

The electronic configuration of Cr along with the values of the quantum numbers $n$ and $l$ are shown.

$n$
$l$
$1 s^{2}$ $1$
$0$
$2 s^{2}$ $2$ $0$
$2 p^{6}$
$2$ $1$
$3 s^{2}$ $3$ $0$
$3 p^{6}$
$3$ $1$
$3 d^{5}$
$3$ $2$
$4 s^{1}$
$4$ $0$
Thus the number of electrons with $l = 1$ is $12$
and the number of electrons with $l = 2$ is $5$

	$n$	$l$
$1 s^{2}$	$1$	$0$
$2 s^{2}$	$2$	$0$
$2 p^{6}$	$2$	$1$
$3 s^{2}$	$3$	$0$
$3 p^{6}$	$3$	$1$
$3 d^{5}$	$3$	$2$
$4 s^{1}$	$4$	$0$

Consider the ground state of Cr atom (Z = 24). The numbers of electrons with the azimuthal quantum numbers, l = 1 and 2 are, respectively: 16 and 412 and 412 and 516 and 5

The electronic configuration of Cr along with the values of the quantum numbers n and l are shown.n l1s21 02s2202p6 213s2303p6313d5324s140Thus the number of electrons with l=1 is 12and the number of electrons with l=2 is 5

Consider the ground state of Cr atom (Z = 24). The numbers of electrons with the azimuthal quantum numbers, $l$ = 1 and 2 are, respectively:
$16$ and $4$
$12$ and $4$
$12$ and $5$
$16$ and $5$