Consider the junction diode as ideal- The value of current flowing through AB is0 A-10-2- A-10-3- A-10-1- A

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Toppr Admin · Accepted Answer

For ideal diode there is no voltage drop across diode- Let I be the current flowing through AB to the right-xA0-Here- VA-x2212-VB-IR or 4-x2212-x2212-6-1000Ior I-10-x2212-2A

Consider the junction diode as ideal. The value of current flowing through $A B$ is

$0 A$
$10^{- 2} A$
$10^{- 3} A$
$10^{- 1} A$

For ideal diode there is no voltage drop across diode. Let I be the current flowing through AB to the right.
Here, $V_{A} - V_{B} = I R$ or $4 - (- 6) = 1000 I$
or $I = 10^{- 2} A$

Consider the junction diode as ideal. The value of current flowing through AB is0A10−2A10−3A10−1A

For ideal diode there is no voltage drop across diode. Let I be the current flowing through AB to the right. Here, VA−VB=IR or 4−(−6)=1000Ior I=10−2A

Consider the junction diode as ideal. The value of current flowing through $A B$ is

$0 A$
$10^{- 2} A$
$10^{- 3} A$
$10^{- 1} A$

For ideal diode there is no voltage drop across diode. Let I be the current flowing through AB to the right.
Here, $V_{A} - V_{B} = I R$ or $4 - (- 6) = 1000 I$
or $I = 10^{- 2} A$