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Consider the nuclear fission ${N e}^{20} \to 2 {H e}^{4} + C^{12}$ Given that the binding energy/nucleon of ${N e}^{20}, {H e}^{4}$ and $C^{12}$ are, respectively, 8.03 MeV, 7.07 MeV and 7.86, identify the corect statement:
8.3 MeV energy will be released
energy of 12.4 MeV will be supplied
energy of 9.72 MeV has to be supplied
energy of 3.6 MeV will be released

A

8.3 MeV energy will be released

B

energy of 9.72 MeV has to be supplied

C

energy of 3.6 MeV will be released

D

energy of 12.4 MeV will be supplied

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