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Question

Consider the nuclear reaction: X200 A 110+B90+ energy .
The binding energy per nucleon for X 200, A 110, B90 is respectively 7.4MeV, 8.2MeV and 8.2Mev. The energy released is
  1. 200MeV
  2. 160MeV
  3. 110MeV
  4. 90MeV

A
110MeV
B
90MeV
C
160MeV
D
200MeV
Solution
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200X110A+90B+Q

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