Consider the statement- Ratio of breadth and length of a hall is 2-5- Complete the following table that shows some possible breadths and lengths of the hall-Breadth of the hall-in metres-10-40Length of the hall-in metres-2550-

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Toppr Admin · Accepted Answer

-i- Length-50-m-dfrac-Breadth-50-dfrac-2-5-5-times-Breadth-50-times 2-By cross-multiplication-ii- Breadth-40-m-dfrac-40-Length-dfrac-2-5-2-times-Length-5-times 40-By cross-multiplication-Length-100-m-

Breadth of the hall(in metres)	$$10$$	$$?$$	$$40$$
Length of the hall(in metres)	$$25$$	$$50$$	$$?$$

Breadth of the hall(in m)	$10$	?	$40$
Length of the hall(in m)	$25$	$50$	?

Consider the statement: Ratio of breadth and length of a hall is $$2:5$$. Complete the following table that shows some possible breadths and lengths of the hall.
Breadth of the hall(in metres) $$10$$ $$?$$ $$40$$
Length of the hall(in metres) $$25$$ $$50$$ $$?$$

(i) Length$$=50$$m
$$\dfrac{Breadth}{50}=\dfrac{2}{5}$$
$$5\times$$Breadth$$=50\times 2$$(By cross-multiplication)
(ii) Breadth$$=40$$m
$$\dfrac{40}{Length}=\dfrac{2}{5}$$
$$2\times$$Length$$=5\times 40$$(By cross-multiplication)
Length$$=100$$m.

Breadth of the hall (in metres)	10	?	40
Length of the hall (in metres)	25	50	?

Consider the statement: Ratio of breadth and length of a hall is $$2:5$$. Complete the following table that shows some possible breadths and lengths of the hall.Breadth of the hall(in metres)$$10$$$$?$$$$40$$Length of the hall(in metres)$$25$$$$50$$$$?$$

(i) Length$$=50$$m$$\dfrac{Breadth}{50}=\dfrac{2}{5}$$$$5\times$$Breadth$$=50\times 2$$(By cross-multiplication)(ii) Breadth$$=40$$m$$\dfrac{40}{Length}=\dfrac{2}{5}$$$$2\times$$Length$$=5\times 40$$(By cross-multiplication)Length$$=100$$m.

Consider the statement: Ratio of breadth and length of a hall is $$2:5$$. Complete the following table that shows some possible breadths and lengths of the hall.
Breadth of the hall(in metres) $$10$$ $$?$$ $$40$$
Length of the hall(in metres) $$25$$ $$50$$ $$?$$

(i) Length$$=50$$m
$$\dfrac{Breadth}{50}=\dfrac{2}{5}$$
$$5\times$$Breadth$$=50\times 2$$(By cross-multiplication)
(ii) Breadth$$=40$$m
$$\dfrac{40}{Length}=\dfrac{2}{5}$$
$$2\times$$Length$$=5\times 40$$(By cross-multiplication)
Length$$=100$$m.