Consider the structure of -Al-2 Me-6- compound and the value of displaystyle-frac-x-y-z- where- x- Maximum number of atoms that can lie in plane having terminal -Al-Me- bonds-y- Total number of -3c-2e- bonds-z- Total number of atoms that are -sp-3- hybridized-

Question

Consider the structure of  -Al-2 Me-6- compound and the value of displaystyle-frac-x-y-z- where- x- Maximum number of atoms that can lie in plane having terminal -Al-Me- bonds-y- Total number of -3c-2e- bonds-z- Total number of atoms that are -sp-3- hybridized-

Toppr Admin · Accepted Answer

Have 2 3C-x2212-2e bonds - y - 2 -Number of atoms lying on a plane having terminal are - - x - 10 -Number of sp3 hybridised atoms are - - z - 8 -So value of x-x2212-yz-10-x2212-28-1

Consider the structure of $A l_{2} M e_{6}$ compound and find the value of $\frac{x - y}{z}$ , where:
$x =$ Maximum number of atoms that can lie in plane having terminal $(A l - M e)$ bonds.
$y =$ Total number of $3 c - 2 e^{-}$ bonds.
$z =$ Total number of atoms that are $s p^{3}$ hybridized.

Have 2 $3 C - 2 e$ bonds ( y = 2 )

Number of atoms lying on a plane having terminal are = ( x = 10 )

Number of $s p^{3}$ hybridised atoms are = ( z = 8 )

So value of $\frac{x - y}{z} = \frac{10 - 2}{8} = 1$

Consider the structure of Al2Me6 compound and find the value of x−yz, where: x= Maximum number of atoms that can lie in plane having terminal (Al−Me) bonds.y= Total number of 3c−2e− bonds.z= Total number of atoms that are sp3 hybridized.

Have 2 3C−2e bonds ( y = 2 )Number of atoms lying on a plane having terminal are = ( x = 10 )Number of sp3 hybridised atoms are = ( z = 8 )So value of x−yz=10−28=1

Consider the structure of $A l_{2} M e_{6}$ compound and find the value of $\frac{x - y}{z}$ , where:
$x =$ Maximum number of atoms that can lie in plane having terminal $(A l - M e)$ bonds.
$y =$ Total number of $3 c - 2 e^{-}$ bonds.
$z =$ Total number of atoms that are $s p^{3}$ hybridized.

Have 2 $3 C - 2 e$ bonds ( y = 2 )

Number of atoms lying on a plane having terminal are = ( x = 10 )

Number of $s p^{3}$ hybridised atoms are = ( z = 8 )

So value of $\frac{x - y}{z} = \frac{10 - 2}{8} = 1$