Question

# Consider the van der Waals constants, $$a$$ and $$b$$, for the following gases.Gas$$Ar$$$$Ne$$$$Kr$$$$Xe$$a/(atm $${dm}^{6}{mol}^{-2}$$1.30.25.14.1b/($${10}^{-2}{dm}^{3}{mol}^{-1}$$3.21.71.05.0Which gas is expected to have the highest critical temperature?

A
$$Kr$$
B
$$Ne$$
C
$$Ar$$
D
$$Xe$$
Solution
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#### Correct option is A. $$Kr$$$$T_C= \dfrac{8a}{27Rb}$$Greater value of $$\cfrac ab$$ higher is $$T_c$$Gas $$\dfrac{a}{b}$$Ar = $$\dfrac {1.3}{3.2}=0.406$$Ne=$$\dfrac{0.2}{1.7}=0.118$$Kr=$$\dfrac{5.1}{1}=5.1$$Xe=$$\dfrac{4.1}{5}=0.82$$$$\because T_c$$ has order: $$Kr>Xe>Ar>Ne$$

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