Consider the van der Waals constants, $$a$$ and $$b$$, for the following gases.
Gas
$$Ar$$
$$Ne$$
$$Kr$$
$$Xe$$
a/(atm $${dm}^{6}{mol}^{-2}$$
1.3
0.2
5.1
4.1
b/($${10}^{-2}{dm}^{3}{mol}^{-1}$$
3.2
1.7
1.0
5.0
Which gas is expected to have the highest critical temperature?
A
$$Ar$$
B
$$Ne$$
C
$$Kr$$
D
$$Xe$$
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Solution
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Correct option is A. $$Kr$$
$$T_C= \dfrac{8a}{27Rb}$$
Greater value of $$\cfrac ab$$ higher is $$T_c$$
Gas $$\dfrac{a}{b}$$
Ar = $$\dfrac {1.3}{3.2}=0.406$$
Ne=$$\dfrac{0.2}{1.7}=0.118$$
Kr=$$\dfrac{5.1}{1}=5.1$$
Xe=$$\dfrac{4.1}{5}=0.82$$
$$\because T_c$$ has order: $$Kr>Xe>Ar>Ne$$
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