Consider three point charges −2Q,+Q, and −Q and four closed surfaces S1,S2,S3, and S4.
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Solution
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Using Gauss's law, electric flux, ϕ=Qenϵ0 where Qen= charge enclosed by the surface. A) For S1:Qen=−2Q+Q=−Q⇒ϕ1=−Qϵ0 thus, A→1,4 B) For S2:Qen=−Q+Q=0⇒ϕ2=0ϵ0=0 thus, B→3 C) For S3:Qen=−2Q+Q−Q=−2Q⇒ϕ3=−2Qϵ0 thus, C→2,4 D) For S4:Qen=0⇒ϕ4=0ϵ0=0 thus, D→3
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