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Question

Consider three point charges 2Q,+Q, and Q and four closed surfaces S1,S2,S3, and S4.

Solution
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Using Gauss's law, electric flux, ϕ=Qenϵ0 where Qen= charge enclosed by the surface.
A) For S1:Qen=2Q+Q=Qϕ1=Qϵ0
thus, A1,4
B) For S2:Qen=Q+Q=0ϕ2=0ϵ0=0
thus, B3
C) For S3:Qen=2Q+QQ=2Qϕ3=2Qϵ0
thus, C2,4
D) For S4:Qen=0ϕ4=0ϵ0=0
thus, D3

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