Consider two alternative mechanism the chlorination of methane- Which step is crucial in deciding which mechanism is not likely to be observed- Mechanism I Mechanism IIA - Cl - 2 -longrightarrow - 2Cl - bullet - A - Cl - 2 -longrightarrow - 2Cl - bullet - B - Cl - bullet - CH - 4 -longrightarrow HCl- - bullet - - CH - 3 - -D - Cl - bullet - CH - 4 -longrightarrow - CH - 3 -Cl- H - bullet -C overset - bullet - C - - H - 3 - Cl - 2 -longrightarrow - CH - 3 -Cl- Cl - bullet -E - H - bullet - Cl - 2 -longrightarrow HCl- Cl - bullet -ABDC

Question

Toppr Admin · Accepted Answer

According to the reaction- step B is crucial and it will tell-xA0-whether-xA0-mechanism is possible or not-1- Initial reactionCl2h-x3BD-x2212-x2192-2Cl-x2219-2- Chain propagationCl-x2219-CH4-x2192-HCl-CH3-x2219-CH3-x2219-Cl2-x2192-CH3Cl-Cl-x2219-3- Chain termination reactionsCl-x2219-Cl-x2219-x2192-Cl2CH3-x2219-CH3-x2219-x2192-CH3-x2212-CH3Cl-x2219-CH3-x2192-CH3Cl

A ${C l}_{2} ⟶ {2 C l}^{∙}$	A ${C l}_{2} ⟶ {2 C l}^{∙}$
B ${C l}^{∙} + {C H}_{4} ⟶ H C l +^{∙} {C H}_{3}$	D ${C l}^{∙} + {C H}_{4} ⟶ {C H}_{3} C l + H^{∙}$
C $∙ C H_{3} + {C l}_{2} ⟶ {C H}_{3} C l + {C l}^{∙}$	E $H^{∙} + {C l}_{2} ⟶ H C l + {C l}^{∙}$

A ${C l}_{2} ⟶ {2 C l}^{∙}$	A ${C l}_{2} ⟶ {2 C l}^{∙}$
B ${C l}^{∙} + {C H}_{4} ⟶ H C l +^{∙} {C H}_{3}$	D ${C l}^{∙} + {C H}_{4} ⟶ {C H}_{3} C l + H^{∙}$
C $∙ C H_{3} + {C l}_{2} ⟶ {C H}_{3} C l + {C l}^{∙}$	E $H^{∙} + {C l}_{2} ⟶ H C l + {C l}^{∙}$

According to the reaction, step B is crucial and it will tell whether mechanism is possible or not.1. Initial reactionCl2hν−→2Cl∙2. Chain propagationCl∙+CH4→HCl+CH3∙CH3∙+Cl2→CH3Cl+Cl∙3. Chain termination reactionsCl∙+Cl∙→Cl2CH3∙+CH3∙→CH3−CH3Cl∙+CH3→CH3Cl