Construct a right angled triangle $$ABC$$ whose $$\angle A = 90^{\circ}$$ and $$ a = 10$$ cm and $$ c = 6$$ cm, from the vertex $$A$$ draw a perpendicular on the hypotenuse.
Steps of construction :
1. Draw a line segment $$AB = 6$$ cm as base.
2. With $$A$$ as centre, draw an angle of $$90^{\circ}$$.
3. With $$B$$ as centre, draw an arc of radius $$10$$ cm which intersects the angle line at $$C$$.
4. Again $$A$$ as centre, draw perpendicular bisector of $$BC$$.
Hence, $$\Delta ABC$$ is the required right angled triangle.