Question

Construct a $△LMN$, if $MN=6.3cm$, $LM=3cm$ and $\angle L={90}^o$.

Answer 1

We need to construct a $△LMN$ with $MN=6.3cm,LM=3cmand\angle L={90}^0$

The following are the steps of construction:-

1) Draw a line segment $LM=3cm$.

2) Draw an arc of any suitable radius taking $L$ as centre intersecting extended line segment $LM$ at $O$ and $Q$.

3) Draw arcs taking same radius and $O,Q$ as centres to intersect at $P$. Join and extend $LP$ to get a line at ${90}^{\circ }$ to $LM$.

4) Now, taking $M$ as centre and $6.3cm$ radius, draw an arc intersecting line through $L$ at $N$.

Hence, $△LMN$ is the required triangle, as shown in the figure above.