Question

Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose sides are $\frac{3}{5}$ time of the corresponding sides of the given triangle.

Answer 1

1) Draw$BC=4cm$

2) Cut arc of $5$ cm from B and arc of $6$ cm from C. Mark point of intersection as A.

3) Draw BD making an acute angle with BC. Mark 5 equal arcs on BD.

4) Join $B_5$ to C, draw a line $B_3{C}^{\prime }$ parallel to $B_{5}C$.

5) Draw a line $C^{\prime }{A}^{\prime }$ parallel to $CA$.

$A^{\prime }B{C}^{\prime }$ ia the required triangle.