Construct a Delta ABC with AB - 4-2 cm- BC - 3-1 cm and CA - 5 cm- What of triangle in this -

Question

Toppr Admin · Accepted Answer

Steps of construction-1-Draw a line segment AB of 4-2 cm-2-From point A cut an arc of 5 cm-3- From point B cut an arc of 3-1 cm-4-Join the point on which both the arcs meet-xA0-x25B3-ABC is the required triangle-It is Scalene triangle-

Construct a $Δ A B C$ with $A B = 4.2$ cm, $B C = 3.1$ cm and $C A = 5$ cm. What type of triangle in this ?

Steps of construction:
1)Draw a line segment $A B$ of $4.2$ cm.
2)From point $A$ cut an arc of $5$ cm.
3) From point $B$ cut an arc of $3.1$ cm.
4)Join the point on which both the arcs meet.

$△ A B C$ is the required triangle.
It is Scalene triangle.

Construct a ΔABC with AB=4.2 cm, BC=3.1 cm and CA=5 cm. What type of triangle in this ?

Steps of construction:1)Draw a line segment AB of 4.2 cm.2)From point A cut an arc of 5 cm.3) From point B cut an arc of 3.1 cm.4)Join the point on which both the arcs meet. △ABC is the required triangle.It is Scalene triangle.

Construct a $Δ A B C$ with $A B = 4.2$ cm, $B C = 3.1$ cm and $C A = 5$ cm. What type of triangle in this ?

Steps of construction:
1)Draw a line segment $A B$ of $4.2$ cm.
2)From point $A$ cut an arc of $5$ cm.
3) From point $B$ cut an arc of $3.1$ cm.
4)Join the point on which both the arcs meet.

$△ A B C$ is the required triangle.
It is Scalene triangle.