Question

Construct parallelogram $ABCD$ with the following measurements:
$AB=4.3cm$, $BC=3.2cm$, $\angle C={120}^o$

Answer 1

$\angle C={120}^0\Rightarrow \angle A={120}^0$ (opposite angles of a parallelogram)

$BC=3.2$ cm, therefore, $AD=3.2$ cm (opposite sides of a parallelogram)

Steps of construction:

1. Draw a line segment $AD=3.2$ cm.

2. At $A$ make an angle of ${120}^0$ and draw $AE$.

3. In off $AD=3.2$ cm on $AE$.

4. With $B$ as center and $3.2$ cm as radius draw an arc.

5. With $D$ as center and $3.2$ cm as radius draw another arc to intersect $C$.

6. Join $BC$ and $DC$.

Hence, $ABCD$ is the required parallelogram is the above drawn figure.