Construct triangle MNO where base NO - 6-7 cm- angle MNO - 45-circ and MO-MN - 2-8 cm-

Question

Toppr Admin · Accepted Answer

1- Draw NO-6-7-xA0-cm-2- Construct -x2220-N-45-x2218- and produce it to X-3- Cut off line segment NP-2-8-xA0-cm on NX-4- Join P-x2212-O-5- Draw a perpendicular bisector of PO such that it intersects NX at M-6- Join M-x2212-O-7- MNO is the required triangle-

Construct $△ M N O$ where base $N O = 6.7 c m$ , $∠ M N O = 45^{\circ}$ and $M O - M N = 2.8 c m .$

1. Draw $N O = 6.7 c m .$
2. Construct $∠ N = 45^{\circ}$ and produce it to $X .$
3. Cut off line segment $N P = 2.8 c m$ on $N X .$
4. Join $P - O$ .
5. Draw a perpendicular bisector of $P O$ such that it intersects $N X$ at $M .$
6. Join $M - O$ .
7. $M N O$ is the required triangle.

Construct △MNO where base NO=6.7 cm, ∠MNO=45∘ and MO−MN=2.8 cm.

1. Draw NO=6.7 cm.2. Construct ∠N=45∘ and produce it to X.3. Cut off line segment NP=2.8 cm on NX.4. Join P−O.5. Draw a perpendicular bisector of PO such that it intersects NX at M.6. Join M−O.7. MNO is the required triangle.

Construct $△ M N O$ where base $N O = 6.7 c m$ , $∠ M N O = 45^{\circ}$ and $M O - M N = 2.8 c m .$

1. Draw $N O = 6.7 c m .$
2. Construct $∠ N = 45^{\circ}$ and produce it to $X .$
3. Cut off line segment $N P = 2.8 c m$ on $N X .$
4. Join $P - O$ .
5. Draw a perpendicular bisector of $P O$ such that it intersects $N X$ at $M .$
6. Join $M - O$ .
7. $M N O$ is the required triangle.