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Question

Convert the given complex number in polar form: i

Solution
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z=i
Let rcosθ=0 and rsinθ=1
On squaring and adding, we obtain
r2cos2θ+r2sin2θ=02+12
r2(cos2θ+sin2θ)=1
r2=1
r=1=1 (Since, r>0)
cosθ=0 and sinθ=1
θ=π2
So, the polar form is
i=rcosθ+irsinθ=cosπ2+isinπ2

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