Copper has face centered cubic -fcc- lattice with interatomic spacing equal to 2-54 mathring-A- the value of lattice constant this lattice is - 1-27mathring-A- 5-08mathring-A- 3-59mathring-A- 2-54mathring-A-

Question

Copper has face centered cubic -fcc- lattice with interatomic spacing equal to  2-54 mathring-A- the value of lattice constant this lattice is - 1-27mathring-A- 5-08mathring-A- 3-59mathring-A- 2-54mathring-A-

Toppr Admin · Accepted Answer

For FCC lattice-4r-x221A-2aGiven- interatomic distance- 2r-2-54-xA0-x2DA-Aa-2-xD7-2r-x221A-2-x221A-2-xD7-2-54-3-59-x2DA-A

Copper has face centered cubic (fcc) lattice with interatomic spacing equal to $2.54 ˚ A$ , the value of lattice constant for this lattice is :
$1.27 ˚ A$
$5.08 ˚ A$
$3.59 ˚ A$
$2.54 ˚ A$

For FCC lattice,

$4 r = \sqrt{2} a$

Given- interatomic distance, $2 r = 2.54 ˚ A$

$a = \frac{2 \times 2 r}{\sqrt{2}} = \sqrt{2} \times 2.54 = 3.59 ˚ A$

Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54˚A, the value of lattice constant for this lattice is :1.27˚A5.08˚A3.59˚A2.54˚A

For FCC lattice,4r=√2aGiven- interatomic distance, 2r=2.54 ˚Aa=2×2r√2=√2×2.54=3.59˚A

Copper has face centered cubic (fcc) lattice with interatomic spacing equal to $2.54 ˚ A$ , the value of lattice constant for this lattice is :
$1.27 ˚ A$
$5.08 ˚ A$
$3.59 ˚ A$
$2.54 ˚ A$

For FCC lattice,

$4 r = \sqrt{2} a$

Given- interatomic distance, $2 r = 2.54 ˚ A$

$a = \frac{2 \times 2 r}{\sqrt{2}} = \sqrt{2} \times 2.54 = 3.59 ˚ A$