Cos-2- 10-circ- - sin-2- 80-circ- - tan-2- 45-circ-

Question

Toppr Admin · Accepted Answer

Cos210-x2218-x2212-sin280-x2218-tan245-x2218-xA0-xA0-cos2-90-x2212-80-x2218-x2212-sin280-x2218-tan245-x2218-xA0-xA0-sin280-x2218-x2212-sin280-x2218-tan245-x2218-xA0- tan245-x2218- 12- 1

${cos}^{2} 10^{\circ} - {sin}^{2} 80^{\circ} + {tan}^{2} 45^{\circ}$

${cos}^{2} 10^{\circ} - {sin}^{2} 80^{\circ} + {tan}^{2} 45^{\circ}$
= ${cos}^{2} (90 - 80)^{\circ} - {sin}^{2} 80^{\circ} + {tan}^{2} 45^{\circ}$
= ${sin}^{2} 80^{\circ} - {sin}^{2} 80^{\circ} + {tan}^{2} 45^{\circ}$
= ${tan}^{2} 45^{\circ}$
= $1^{2}$
= $1$

cos210∘−sin280∘+tan245∘

cos210∘−sin280∘+tan245∘ = cos2(90−80)∘−sin280∘+tan245∘ = sin280∘−sin280∘+tan245∘ = tan245∘= 12= 1

${cos}^{2} 10^{\circ} - {sin}^{2} 80^{\circ} + {tan}^{2} 45^{\circ}$

${cos}^{2} 10^{\circ} - {sin}^{2} 80^{\circ} + {tan}^{2} 45^{\circ}$
= ${cos}^{2} (90 - 80)^{\circ} - {sin}^{2} 80^{\circ} + {tan}^{2} 45^{\circ}$
= ${sin}^{2} 80^{\circ} - {sin}^{2} 80^{\circ} + {tan}^{2} 45^{\circ}$
= ${tan}^{2} 45^{\circ}$
= $1^{2}$
= $1$